10x^2-18=-88x

Solution for 10x^2-18=-88x equation:

10x^2-18=-88x

We move all terms to the left:

10x^2-18-(-88x)=0

We get rid of parentheses

10x^2+88x-18=0

a = 10; b = 88; c = -18;
Δ = b2-4ac
Δ = 882-4·10·(-18)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-92}{2*10}=\frac{-180}{20}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+92}{2*10}=\frac{4}{20}
=1/5
$